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Alina [70]
3 years ago
7

While waiting to be seated at a restaurant, Jason receives a customer loyalty coupon through an app on his mobile phone for half

off a dessert with the purchase of an entrée. This use of a location-based software application is designed to promote which of the 4E framework objectives?
Computers and Technology
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

Excite

Explanation:

The 4E framework objectives are:

EXCITE: customer are excited with relevant offer

EDUCATE: customer are educated about ongoing offers

EXPERIENCE: customer experience is improved with regards to the product

ENGAGE: customer is engaged to share feedback.

The use of location-based software application will help Jason to be excited. In this case Jason will be excited about the offer.

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Write a program whose inputs are three integers, and whose outputs are the largest of the three values and the smallest of the t
arlik [135]

Answer:

import java.util.*;

public class Main

{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    System.out.print("Enter the first number: ");

    int n1 = input.nextInt();

    System.out.print("Enter the second number: ");

    int n2 = input.nextInt();

    System.out.print("Enter the third number: ");

    int n3 = input.nextInt();

 System.out.println("largest: " + LargestNumber(n1, n2, n3));

 System.out.println("smallest: " + SmallestNumber(n1, n2, n3));

}

public static int LargestNumber(int num1, int num2, int num3){

    int largestNum = 0;

    if(num1>=num2 && num1>=num3)

        largestNum = num1;

    else if(num2>=num1 && num2>=num3)

        largestNum = num2;

    else if(num3>=num1 && num3>=num2)

        largestNum = num3;

       

    return largestNum;

}

public static int SmallestNumber(int num1, int num2, int num3){

    int smallestNum = 0;

    if(num1<=num2 && num1<=num3)

        smallestNum = num1;

    else if(num2<=num1 && num2<=num3)

        smallestNum = num2;

    else if(num3<=num1 && num3<=num2)

        smallestNum = num3;

       

    return smallestNum;

}

}

Explanation:

Create function called LargestNumber that takes three parameters, num1, num2, num3. Find the largest number using if else structure among them and return it. For example, if num1 is both greater than or equal to num2 and num3, then it is the largest one.

Create function called SmallestNumber that takes three parameters, num1, num2, num3. Find the smallest number using if else structure among them and return it. For example, if num1 is both smaller than or equal to num2 and num3, then it is the smallest one.

Inside the main, ask the user for the inputs. Call the functions and print the largest and smallest.

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Explanation:

3 0
3 years ago
Statement: There are two files. One file, "badIP_list.txt" has a listing of known bad IP addresses. These addresses were extract
lapo4ka [179]

Answer:

See explaination

Explanation:

SOURCE CODE IN PYTHON:

inp=open('badIP_list.txt', 'r') #opening file for input

badIPs=[i.rstrip('\n') for i in inp.readlines()] #reading bad IPs

inp.close() #closing file

inp=open('server_logs.txt', 'r') #opening file for input

IPs=[i.rstrip('\n') for i in inp.readlines()] #reading all IPs from log

inp.close() #closing file

uniqueBadIPs=[] #to store unique bad IPs

countBadIPs=0 #to store count of bad IPs

countIPs=0 #to store count of all IPs

for IP in IPs: #iterating through the log of IPs

if IP in badIPs: #checking if IP is bad

countBadIPs+=1

if IP not in uniqueBadIPs: #checking if bad IP is unique

uniqueBadIPs.append(IP)

countIPs+=1

out=open('filter_list.txt', 'w') #opening file for output

out.write('_________________________________________________________\n')

out.write('Date : 26/07/2018\nName : Last, First\nMajor: CS\n\n')

out.write('Server logs contained these known bad IP addresses:\n')

for IP in uniqueBadIPs: #output the unique bad IPs

out.write(IP+'\n')

out.write('\n')

out.write('Total unique known bad IP\'s detected:\n'+str(len(uniqueBadIPs))+'\n\n')

out.write('Percentage of bad IP addresses in server logs:\n{:.2f}%\n'.format(countBadIPs*100/countIPs))

out.write('_________________________________________________________')

out.close() #closing file

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