Answer:
There are seven oxygen atoms in total on the product side.
Explanation:
The oxygen atom is present in both the species of CO₂ and H₂O. As there are two molecules of CO₂, so the number of oxygen atoms from it will be 4. There are three molecules of H₂O in the product side so oxygen atoms from it will be three. So, the total number of oxygen from both species is seven.
Answer:
The rate of disappearance of 
for this period is
Explanation:
Initial concentration of = x = 0.0138 M
Final concentration of = y = 0.00886 M
Time elapsed during change in concentration = Δt = 374 s
Change in concentration ,![\Delta [NO_2]](https://tex.z-dn.net/?f=%5CDelta%20%5BNO_2%5D)
= y - x = 0.00886 - 0.0138 M = -0.00494 M
The rate of disappearance of for this period is:
![\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BNO_2%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B-0.00494%20M%7D%7B374%20s%7D%3D-1.32%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
They come up with a hypothesis (question to investigate), then they work out what variables and what they will be measuring, keeping the same and changing in the experiment
Answer : The correct option is, (1) 0
Explanation :
Oxidation state or oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with sign (+ and -) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
As per question, 'Mn' atom is a free element that means it is present in their elemental state then the oxidation state will be zero.
Hence, the correct option is, (1) 0
Volume Ba(OH)2 = 23.4 mL in liters :
23.4 / 1000 => 0.0234 L
Molarity Ba(OH)2 = 0.65 M
Volume HNO3 = 42.5 mL in liters:
42.5 / 1000 => 0.0425 L
number of moles Ba(OH)2 :
n = M x V
n = 0.65 x 0.0234
n = 0.01521 moles of Ba(OH)2
Mole ratio :
<span>Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O
</span>
1 mole Ba(OH)2 ---------------- 2 moles HNO3
0.01521 moles ----------------- moles HNO3
moles HNO3 = 0.01521 x 2 / 1
moles HNO3 = 0.03042 / 1
= 0.03042 moles HNO3
Therefore:
M ( HNO3 ) = n / volume ( HNO3 )
M ( HNO3 ) = 0.03042 / 0.0425
M ( HNO3 ) = 0.715 M
