Answer:
Explanation:
You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.
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<u>1. Number of moles of H</u><u>₂</u>
- number of moles = mass in grams / molar mass
- molar mass of H₂ = 2.016g/mol
- number of moles = 6.00grams / 2.016g/mol = 2.97619mol
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<u>2. Number of moles of NH</u><u>₃</u>
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i) Chemical equation:
ii) Mole ratio:
iii) Proportion:
- x mol NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂
<u>3. Volume of NH₃</u>
- V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm
Answer:
290.32 g
Explanation:
First we <u>calculate the volume</u> of the cube:
- Volume = (3.20 cm)³ = 32.768 cm³
Now we <u>convert cubic centimeters to mililiters</u>:
- 32.768 cm³ * 1 mL / 1 cm³ = 32.768 mL
Finally we <u>calculate the mass</u>, using the <em>equation for density</em>:
- mass = 8.86 g/mL * 32.768 mL = 290.32 g
