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Slav-nsk [51]
3 years ago
5

Find the slope of a line perpendicular to y=3×+7​

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

-1/3

Step-by-step explanation:

y = 3x+7

This is in the form y = mx+b

The slope is m so it is equal to 3

Perpendicular lines have slopes that are negative reciprocals

m perpendicular = - (1/3)

                   

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2(b+3c) equivalent expressions<br>Options: <br><br>3(b+2c)<br>(b+3c) +(b+3c)<br>None of the above
Lana71 [14]
2(b + 3c) → We first need to simplify this.

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~Hope I helped!~



5 0
3 years ago
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vlabodo [156]

Answer:

(9.5, 0) is in quadrant I. (-4, 7) is in quadrant II. (-1, -8) is in quadrant III.

Step-by-step explanation:

The negative signs say everything (quite literally). If there are no negative signs, it is in quadrant I. If there is one in the x-axis (the first number in an ordered pair), it is in quadrant II. If there are 2 negative signs, it is in quadrant III, and if there is one in the y-axis (the second number in an ordered pair), it is in quadrant IV.

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