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Vlad1618 [11]
3 years ago
8

What is the equation of this trend line?

Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

The trend line is N = -2M + 110

Step-by-step explanation:

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Segment EF is a mid segment of triangle ABC. If EF = 15 cm, what is the measure of segment BC?
vaieri [72.5K]

Answer:

30

Step-by-step explanation:

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3 years ago
What is the value of the expression when a = 4, b = 3 , and c = 10?
daser333 [38]

Answer:

3a4b-c

3(4)4(3)-10

12(12)-10

144-10

=134

Step-by-step explanation:

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3 years ago
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Determine the values of x when f(x)=40 for the function f(x)=2(x-3)^2-8
SpyIntel [72]

Answer:

x = 3 ± \sqrt{24}

or

x = 3 + \sqrt{24}, x = 3 - \sqrt{24}

Step-by-step explanation:

given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40

So, we plug in 40 for f(x) in the 1st equation and solve for x.  (Aim to got x on its own)

40 = 2 (x - 3)^2 - 8

+ 8          + 8

-----------------------------

48 = 2 (x - 3)^2

/2            /2

-----------------------------

24 = (x - 3)^2

square root both sides

--------------------

\sqrt{24} = x - 3

x = 3 ± \sqrt{24}

5 0
3 years ago
How much does an ice cream cost with 11 ounces of toppings?
oksano4ka [1.4K]

<em>$3.00 for ice cream </em>

<em> </em>

<em>+ $2.00 for the 4 ounces of toppings </em>

<em> </em>

<em>$5.00 </em>

<em> </em>

<em>hope it helps!!</em>

<em>SMILE!!</em>

4 0
3 years ago
A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
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