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xz_007 [3.2K]
3 years ago
7

Which is the simplified form of the expression (6 to the power of -2 times 6 to the power of 5) to the -3rd power?

Mathematics
2 answers:
julsineya [31]3 years ago
7 0

Answer:

B. 1/6^9

Step-by-step explanation:

6^-2 = 1/6^2

1/6^2 * 6^5 = 6^5/6^2 = 6^3

6^(3 * -3) = 6^-9= 1/6^9

mr_godi [17]3 years ago
3 0

Answer:

<h2>B) 1 over (6 to the power of 9)</h2>

Step-by-step explanation:

\left(6^{-2}\cdot6^5\right)^{-3}\qquad\text{use}\ a^n\cdot a^n=a^{n+m}\\\\=(6^{-2+5})^{-3}=(6^3)^{-3}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=6^{(3)(-3)}=6^{-9}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{6^9}

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The quotient of a number and 7 is greater than or equal to 20
Rina8888 [55]

Answer:

a is greater than or equal to 140

Step-by-step explanation:

Multiply both sides by 7, which cancels out the 7 and turns 20 into 140

6 0
2 years ago
When dividing the polynomial using synthetic division, which of the following setup boxes would be used?
Galina-37 [17]

The setup boxes in the synthetic division are (b)

<h3>How to determine the setup boxes?</h3>

The dividend is given as:

x^3 + 4x^2 + x - 6

The divisor is given as:

x - 2

Set the divisor to 0

x - 2 = 0

Solve for x

x = 2

Remove the variables in the dividend

1 + 4 + 1 - 6

Remove the arithmetic signs

1  4  1 - 6

So, the setup is:

2 | 1  4  1 - 6

Hence, the setup boxes are (b)

Read more about synthetic division at:

brainly.com/question/12951962

#SPJ1

8 0
2 years ago
Convert to standard form: F(x) = 2x + 4
mote1985 [20]
The answer will be F=2x/x + 4/x
7 0
3 years ago
What is "h"? h+1/2=3 1/4
yarga [219]
For this equation
H+1/2= 3 1/4

H is a variable, so it must have a value to it. So it would be 2.75+1/2= 3 1/4
Or 3 1/4 / 1/2 = 2.75

6 0
3 years ago
Help me please :((: thank u
I am Lyosha [343]

Hey there!

In order for you to find the one that is equivalent to the given expression is to COMBINE YOUR LIKE TERMS then work from there!

12q + q^2 - 8 + q = ?

(q^2) + (12q + q) + (-8)

q^2 = q^2 since it doesn't have any like term(s)

12q + q = 12q + 1q = 13q

-8 = -8 since it doesn't have any like term(s)

Put all the numbers we solved for in An equation and Thats your answer!

If you did it correctly you should have: q^2 + 13q - 8

Answer: q^2 + 13q - 8 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
3 years ago
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