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Dafna1 [17]
3 years ago
10

3 ft 4 ft What is the length of the hypotenuse

Mathematics
1 answer:
elena-s [515]3 years ago
7 0
The length of the hypotenuse is 5ft
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
c^2=25
sqrt c^2= sqrt 25
c=5
Therefore, the length of the hypotenuse is 5th
:)
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The graph depicts the growth and costs using of line segment use the midpoint formula to approximate the cost during the year 19
marysya [2.9K]

Answer:

The approximate cost during the year 1987 was $7,533

Step-by-step explanation:

The complete question in the attached figure

we have

y -----> is the cost in dollars

x -----> is the year

Looking at the graph we have the points

(1983,5,047) and (1991, 10,019)

To determine the cost in the year 1987, find out the midpoint between the two given points

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

substitute the values

M=(\frac{1983+1991}{2},\frac{5,047+10,019}{2})

M=(1987,7,533)

therefore

The approximate cost during the year 1987 was $7,533

7 0
4 years ago
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Marat540 [252]
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8 0
3 years ago
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shtirl [24]

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8 0
3 years ago
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
3 years ago
How do i solve 6x=5x+7 by using solving systems by elimination?
klio [65]
I just learned about it. Simple!

6x=5x+7
Subtract 5x from both sides.
-5x -5x
You end up with
1x=7   or  x=7



7 0
3 years ago
Read 2 more answers
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