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klemol [59]
3 years ago
15

Kyle is buying a new car. The car can be driven 24.3 miles with one gallon of gas. The gas tank can hold 15.3 gallons of gas. Ky

le wants to know how far he can travel on a full tank of gas. Which method and reasoning can Kyle use to find the distance he can travel in miles?
Mathematics
2 answers:
ipn [44]3 years ago
4 0
Im sure the answer is 371.79
marshall27 [118]3 years ago
3 0

Answer:

Unitary method

Total distance=371.79 miles

Step-by-step explanation:

We are given that Kyle is buying a new car.

The car driven in one gallon of a gas =24.3 miles

The gas tank holds=15.3 gallons

We have to find the method and reasoning can Kyle use to find the distance he can travel in miles.

We have to find the distance travel in 15.3 gallons of a gas

So , we are using unitary method .

Unitary method : When we want to find more than one units  with the help of one unit by multiplying

Because we are finding in 15. 3 gallons which is more than one and we are given that in 1 gallon of gas car travel 24. 3 miles

Total distance =24.3\times 15.3=371.79 miles

Hence, the distance Kyle can travel in 15.3 gallons of gas=371.79 miles

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Use the least common denominator to write an equivalent fraction for each fraction. 5/6 and 2/9
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5/6 and 2/9......least common denominator is 18
so 5/6 = 15/18 and 2/9 = 4/18

1/12 and 3/8...least common denominator is 24
so 1/12 = 2/24 and 3/8 = 9/24

5/9 and 2/15...least common denominator is 45
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3 0
3 years ago
This was due yesterday please help​
Marianna [84]

Answer: 2.1925153x10 to the 3rd

Step-by-step explanation: hope it helps

3 0
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Suppose you make hot chocolate. It's too hot to drink, so you put it in the freezer to cool it off. If the original temperature
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Step-by-step explanation:

8 0
2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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