The are is eleven because 2×11= 22
Answer:
B is the Y-Intercept of the graph/equation
Step-by-step explanation:
Let
. The gradient of
at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.
So the tangent plane has equation

Compute the gradient:

Evaluate the gradient at the given point:

Then the equation of the tangent plane is

Answer:
C. x ≈ 0.28
Step-by-step explanation:
A graphing calculator solution is attached. It shows ...
x ≈ 0.28
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You can divide both sides of the given equation by 5, then take natural logs and divide by 5 again.
5e^(5x) = 20 . . . . . . given
e^(5x) = 4 . . . . . . . . divide by 5
5x = ln(4) . . . . . . . . take natural logs
x = ln(4)/5 . . . . . . . divide by 5
x ≈ 0.277259 ≈ 0.28
They are have s0mething that is positive. This is what I think.