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steposvetlana [31]
2 years ago
9

A family is preparing backpacks filled with school supplies to donate to children in need. They have 9 pencils and 6 notebooks.

If they want to make all the backpacks the same, with no school supplies left over, what is the greatest number of backpacks they can fill?
I need the help ASAP please
Mathematics
1 answer:
mel-nik [20]2 years ago
6 0

Answer:3

Step-by-step explanation: i think

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1. no i'm a guy unless u want to see my johnny sin thing 2. yes who dsen't

Step-by-step explanation:

7 0
3 years ago
Please answer This question...​
mestny [16]

Answer:

(2) 4, 7, 9; 2, 5, 6; 1, 3, 8

Step-by-step explanation:

Let's group them based on how many lines they have inside the shape...

0 lines: 4, 7, 9

2 lines: 2, 5, 6

3 lines: 1, 3, 8

Therefore the answer is (2) 4, 7, 9; 2, 5, 6; 1, 3, 8

4 0
2 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
This is an equation that indicates how the variables are related to one another.
Misha Larkins [42]
Yes if they relate to one another using an = sign
7 0
3 years ago
Can a pair of lines be both parallel and perpendicular? explain
alina1380 [7]
No, the 2 lines can never ever be both parallel and perpendicular if I'm not mistaken. This is because a set of parallel lines will never touch each other at all. However perpendicular lines are two lines that meet up to get an angle of 90. You cannot have two lines that never touch and touch at the same time.
6 0
3 years ago
Read 2 more answers
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