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3 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT

Mathematics

1 answer:

fredd [130]3 years ago

7 0

Here you go!! It's always best to graph these questions, if you have graph paper near.
If not there are online graphing websites to use!! :))

ANSWER: Choice D (4th answer)

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Lydia spent 4/5 of her money on a mobile phone and 2/3 of the remaining amount on a bag. She had $60 left. How much more money d

KengaRu [80]

The answer is 600 because 1 out 3 is 60 so to find the bag multiply by two while to find 1 out 5 of her monet take 60 times 3 which is 180. 180 times 4 is the money she spent on her mobile phone so take the money spent on her mobile phone(720)minus the amount of money spent on the bag(120)

5 0

3 years ago

Write 60 as the product of two factors

Ilya [14]

Use a factor tree to express 60 as a product of prime factors. So the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 2 2 × 3 × 5.

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3 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

Could some one pllz give me real answers

timofeeve [1]

Answer:

See below

Step-by-step explanation:

You just need 1/4 of everything:

1/4 c peanut butter

1/4 c brown sugar

1/4 c gran sugar

1/4 c butter

1/2 egg

1/4 tsp baking soda

1/4 tsp baking powder

1/4 tsp vanilla

5/8 c flour

8 0

3 years ago

Read 2 more answers

Mrs. Wigen conducted a survey in her math class. She asked each of her students to tell her how many pets they have at home. The

Lera25 [3.4K]

Answer:

4 : 25 to round off we have to see that

4 : 25 to round off we have to see that If in ones place it is more than 5 or not

4 : 25 to round off we have to see that If in ones place it is more than 5 or not if yes we will add to 1 no to tenths place

4 : 25 to round off we have to see that If in ones place it is more than 5 or not if yes we will add to 1 no to tenths place Finally 4 : 25 it has 5 in its ones place

<h3>So the answer will be 4 : 30 </h3>

7 0

3 years ago