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4vir4ik [10]
2 years ago
12

Given the sequence is defined by the explicit definition t_n=2^n-nt n = 2 n − n, find the 5th term of the sequence. (ie: t_5t 5)

Mathematics
2 answers:
babymother [125]2 years ago
8 0

Answer:

If the n-th term of a sequence  be , t(n) equal to  2^{n} - n  then the 5-th term is 27 but if the n-th term is (2n -n) then the 5-th term is 5.

Step-by-step explanation:  

If the n-th term of a sequence  be , t(n) = 2^{n} - n

then, the 5-th term is given by,  t(5) = 2^{5}- 5

                                                          = 32 - 5

                                                          = 27

If the n-th term of a sequence  be , t(n) = 2n - n = n

then, the 5-th term is given by,  t(5) = 5

marissa [1.9K]2 years ago
7 0

<em>*100% CORRECT ANSWERS</em>

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<h3>How to determine the inverse </h3>

The steps involved in determining the inverse of a function are;

  • Replace f(x) with y in the equation describing the function
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If f(x) = 4/5x + 13

y = 4/5y + 13

y = 4 + 65 /5y

f^-1 = 4 + 65 /5y

f^-1(x)= 69/5y

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y = 3/y + 10 + 4

y = 3 + 4y + 10/(y + 10)

y = 13 + 4y/(y + 10)

f^-1(x) = 13 + 4y/(y + 10)

Thus, the inverse of the functions is 69/5y and 13 + 4y/(y + 10)

Learn more about functions here:

brainly.com/question/6561461

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