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3 years ago

Do the rules described result in a fair situation?

Mathematics

1 answer:

AysviL [449]3 years ago

4 0

yes it would be yes so yes

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3 years ago

Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of

Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

$SI = \frac{P \times T \times R}{100}$

First account: $SI=\frac{x \times 1 \times 12}{100}$

Second account : $SI =\frac{(6000-x) \times 1 \times 7}{100}$

We are given that At the end of the first year he had earned $590 in interest.

So, $\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400$

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

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3 years ago

What’s 7= y-2/3 if you’re solving for y

Rus_ich [418]

Answer:

y = 23/3

Step-by-step explanation:

Simplify both sides of equation

7 = y + -2/3

Flip equation

y + -2/3 = 7

Add 2/3 to both sides

y + -2/3 + 2/3 = 7 + 2/3

y = 23/3

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