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Anastaziya [24]

4 years ago

8

A difference between crt monitors and flat-panel displays is that most flat-panel displays use digital signals to display images

, while crt monitors use ____.

Computers and Technology

1 answer:

scoundrel [369]4 years ago

7 0

some crt monitors use analog signals such as rca, coaxial, or bnc connectors.

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Suppose that the following elements are added in the specified order to an empty binary search tree: Kirk, Spock, Scotty, McCoy,

patriot [66]

Answer:

Pre-order: Kirk, Chekov, Khaaaan, Spock, Scotty, McCoy, Sulu, Uhuru

In-order: Chekov, Khaaaan, Kirk, McCoy, Scotty, Spock, Sulu, Uhuru

Post-order: Khaaaan, Chekov, McCoy, Scotty, Sulu, Uhuru, Spock, Kirk

Explanation:

The binary search tree is described in the diagram below.

The pre-order traversal of the binary tree gets the root, then the left node and right node. The in-order traversal picks the left node, the root node, and then the right node while the post-order traversal of the binary tree follows the left node, right node, and then the root node.

6 0

3 years ago

You have stumbled on an unknown civilization while sailing around the world. The people, who call themselves Zebronians, do math

marshall27 [118]

Answer:

a. 6 bits

b. 1

Explanation:

Ans (a)

40 Characters need to be represent by binary coded Zebronian (BCZ) , So You will need 6 bits.

5 bits wold only give you 32 = 2 x 2 x 2 x 2 x 2 unique characters.

So 6 bits would allow you to represent 64 characters.

Ans(b)

BCD = Binrary Coded Decimal is very common in electronics, particularly it displays numerical data.

BCD Encodes each digit of a decimal number into 4 digit binary form.

Each decimal digit is indiviidually converted to oits binary equivalent

For Example : 146 , the decimal degits are replaced by 0001 , 0100 and 0110 respectively

Addition

1 0 = 10 is binary value of 2 2

+1 1 = 11 is binary value of 3 + 3

---------- -----------

1 0 1 5 Ans

Subtraction

1 1= binary value of 3 3

- 1 0 = binary value of 2 - 2

--------- -----------

0 1 1 Ans

6 0

3 years ago

Design a class named QuadraticEquation for a quadratic equation ax^2+bx+x=0. The class contains: **private data fields a, b, and

LenaWriter [7]

Answer:

<em>C++</em>

///////////////////////////////////////////////////////////////////////////////////////////

#include <iostream>

using namespace std;

//////////////////////////////////////////////////////////////////

class QuadraticEquation {

int a, b, c;

public:

QuadraticEquation(int a, int b, int c) {

this->a = a;

this->b = b;

this->c = c;

}

////////////////////////////////////////

int getA() {

return a;

}

int getB() {

return b;

}

int getC() {

return c;

}

////////////////////////////////////////

// returns the discriminant, which is b2-4ac

int getDiscriminant() {

return (b*2)-(4*a*c);

}

int getRoot1() {

if (getDiscriminant() < 0)

return 0;

else {

// Please specify how to calculate the two roots.

return 1;

}

}

int getRoot2() {

if (getDiscriminant() < 0)

return 0;

else {

// Please specify how to calculate the two roots.

return -1;

}

}

};

//////////////////////////////////////////////////////////////////

int main() {

return 0;

}

4 0

4 years ago

If no other row matches, the router will select the ________ row as its best match. First Last either First or Last, depending o

zzz [600]

Answer:

Last

Explanation:

Routing is a term in engineering which involves the process of selecting a path for traffic in a network or across multiple networks. It is applicable in circuit-switched networks, such as the public switched telephone network (PSTN), and computer networks, such as the Internet. It is mostly used as a term for IP Routing.

Hence, in IP Routing, the first step is comparing the packet's destination IP address to all rows, followed by selecting the nest-match row. However, If no other row matches, the router will select the LAST row as its best match.

6 0

4 years ago

I'm using assembly language. This is my assignment. I kinda confused about how to write code for this assignment. Can anyone exp

Brut [27]

Answer:

oid changeCase (char char_array[], int array_size ) {

__asm{

mov eax, char_array;

mov edi, 0;

readArray:

cmp edi, array_size;

jge exit;

mov ebx, edi;

shl ebx, 2;

mov cl, [eax + ebx];

check:

//working on it

cmp cl, 0x41;

jl next_indx;

cmp cl, 0x7A;

jg next_indx;

cmp cl, 'a';

jl convert_down;

jge convert_up;

convert_down:

or cl, 0x20; //make it lowercase

jmp write;

convert_up:

and cl, 0x20;

jmp write;

write:

mov byte ptr [eax + ebx], cl

next_indx:

inc edi;

exit:

cmp edi, array_size;

jl readArray;

mov char_array, eax;

}

}

Explanation:

Move char_array to eax as it is base image .
Use ebx as offset .
Use ecx as the storage register .
check if cl is <= than ASCII value 65 (A) .

6 0

4 years ago