Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If
of a page occupies 1 kB of memory, we can calculate how much memory a book will take

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.
Lol just lay back and unleash your gamer side
Answer:
The program to this question can be given as follows:
Program:
#defining variable quarters, dimes, and nickels.
quarters=int(input("Enter value of quarters: ")) #input value by user dimes=int(input("Enter value of dimes: ")) #input value by user nickels=int(input("Enter value of nickels: ")) #input value by user
#defining variable pennies
pennies = ((25*quarters)+(10*dimes)+(5*nickels))
#calculate value in pennies variable
print('Total number of coins in pennies is: ',pennies)#print value
Output:
Enter value of quarters: 3
Enter value of dimes: 2
Enter value of nickels: 1
Total number of coins in pennies is: 100
Explanation:
In the above python program code, firstly three variable "quarters, dimes, and nickels", all of these variable uses input function, that is used to take input value from the user side, in these variable, an int is used that defined, that user input only integer value.
- After taking input from the user a new variable "pennies" is defined, which is uses the user input values and calculates its addition.
- In the next line, print function is used, which uses variable "pennies" to print its calculated value.
Answer:
def find_max(num_1, num_2):
max_val = 0.0
if (num_1 > num_2): # if num1 is greater than num2,
max_val = num_1 # then num1 is the maxVal.
else: # Otherwise,
max_val = num_2 # num2 is the maxVal
return max_val
max_sum = 0.0
num_a = float(input())
num_b = float(input())
num_y = float(input())
num_z = float(input())
max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)
print('max_sum is:', max_sum)
Explanation:
I added the missing part. Also, you forgot the put parentheses. I highlighted all.
To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)