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Serhud [2]
3 years ago
7

I don't know how to simplify

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
(5-2/x)/4-3/x^2

after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3

now u can solve it


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If 100 people drink 1.5 cups of coffee a day and the cost per cup is .40 how much would it cost to provide coffee for the whole
N76 [4]

Answer:

It would cost <u>15600</u> to provide coffee for the whole year.

Step-by-step explanation:

Given:

If 100 people drink 1.5 cups of coffee a day and the cost per cup is .40

Now, to find the cost to provide coffee for the whole year if you're place is open 5 days a week.

So, we have the unit rate, and we have to find the cost of 1.5 cup by multiplying 0.40.

<em>1.5 cup of coffee cost </em>1.5\times 0.40=0.60.

<em>Thus, 1.5 cup cost 0.60.</em>

<em>If, 100 people drink 1.5 cups. </em>

<em>Then, total cost of  100 people drinking 1.5 cups of coffee = </em>100\times 0.60=60<em />

<em>As, place is open 5 days a week.</em>

So, to get the cost of coffee in 5 days of a week we multiply 5 by 60:

5\times 60\\\\=300.

<em>Hence, the cost of coffee in a week is 300.</em>

<em>In 1 year there are 52 weeks.</em>

Now, to get the cost for the whole year we multiply 52 by 300:

52\times 300\\\\=15600.

Therefore, it would cost 15600 to provide coffee for the whole year.

6 0
3 years ago
Read 2 more answers
What would be the best way to select an unbiased population sample for the following topic: How do people get to
RoseWind [281]
Randomly survey 20 people
7 0
3 years ago
Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn.
Citrus2011 [14]

The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is  10,000 ft².  That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around.  10,000 ft² ... no mas !

When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
       (200 - 0) = 200
       (100 - 2) = 98
       (200 - 2) = 198
       (100 - 4) = 96    

Second lap:
       (200 - 4) = 196
       (100 - 6) = 94
       (200 - 6) = 194
       (100 - 8) = 92   

Third lap:
       (200 - 8) = 192
       (100 - 10) = 90
       (200 - 10) = 190
       (100 - 12) = 88 

These are the lengths of each strip.  They're 2-ft wide, so the area
of each one is (2 x the length). 

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it.  So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
       (200 - 12) = 188
       (100 - 14) = 86
       (200 - 14) = 186
       (100 - 16) = 84 

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft².  If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

         (200 x 100),  (196 x 96),  (192 x 92),  (188 x 88),  (184 x 84) ... etc.

and the areas of their rectangular strips are
           1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
       So the next few laps are 
               1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc. 

How much area do we have now:

             After 9 laps,    Area =   9,648-ft²
             After 10 laps,  Area = 10,560-ft².

And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².   


There must still be an easier way to do it.  For now, however, I'll leave it
there, and go with my answer of:  During the 10th lap.

5 0
3 years ago
Please show how you got the answer, thanks.
FrozenT [24]

Answer:

15.7 feet

Step-by-step explanation:

What we are looking for here is the perimeter/circumference of the table. The formula for the circumference of a circle is diameter x pi. The diameter is 2x the radius so I did 5 x 3.14, 3.14 being in place for pi. Hope this helps! : )

5 0
3 years ago
Point S is on line segment RT.Given ST = 2x, and RT = 4x, and RS = 4x – 4,
Lorico [155]

Answer:

2

Step-by-step explanation:

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