Answer:
(A) with .
(B) with
(C) with
(D) with ,
Step-by-step explanation
(A) We can see this as separation of variables or just a linear ODE of first grade, then . With this answer we see that the set of solutions of the ODE form a vector space over, where vectors are of the form with real.
(B) Proceeding and the previous item, we obtain . Which is not a vector space with the usual operations (this is because ), in other words, if you sum two solutions you don't obtain a solution.
(C) This is a linear ODE of second grade, then if we set and we obtain the characteristic equation and then the general solution is with , and as in the first items the set of solutions form a vector space.
(D) Using C, let be we obtain that it must satisfies and then the general solution is with , and as in (B) the set of solutions does not form a vector space (same reason! as in (B)).
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Answer:
4
x
2
−
28
x
+
49
Step-by-step explanation:
Its Not The Answer But Its Your Question Simplified
The answer is triangle ACD is congruent to triangle ABD.
Answer:10 is the area
Step-by-step explanation: