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Evgen [1.6K]
3 years ago
14

What are two same numbers that multiply each other to get 121

Mathematics
2 answers:
Leni [432]3 years ago
7 0

The numbers are 11.

11*11= 121.

Elenna [48]3 years ago
4 0

11

11 times 11 equals 121.

11 squared equals 121.

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A large but sparsely populated county has two small hospitals, one at the south end of the county and the other at the north end
mojhsa [17]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In point a:

Although both variables are non - stationary, for both the respective pmf, multiply all pmf principles. For example:

\to P(x=0,y=0)=P(x=0)\times P(y=0)

                                     X                                                    

                   0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ 2\ \ \ \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \  pmf Y

0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.01 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.02 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.03\ \ \ \ \ \ \ \ \ \ \ \ \ \  0.02\ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.02\ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.1

Y \ \ \ \ \ \ \ \ \ \ \ 1  \ \ \ \ \ \ \ \ \ \ \ 0.03 \ \ \ \ \ \ \ \ \ \ \ 0.06 \ \ \ \ \ \ \ \ \ \ \ 0.09 \ \ \ \ \ \ \ \ \ \ \ 0.06 \ \ \ \ \ \ \ \ \ \ \ 0.06 \ \ \ \ \ \ \ \ \ \ \ 0.3

              2 \ \  \ \ \ \ \ \ \ 0.04\ \  \ \ \ \ \ \ \ 0.08\ \  \ \ \ \ \ \ \ 0.12 0.08\ \  \ \ \ \ \ \ \ 0.08\ \  \ \ \ \ \ \ \ 0.4\\\\ 3\ \  \ \ \ \ \ \ \ 0.02\ \  \ \ \ \ \ \ \ 0.04\ \  \ \ \ \ \ \ \ 0.06\ \  \ \ \ \ \ \ \ 0.04\ \  \ \ \ \ \ \ \ 0.04\ \  \ \ \ \ \ \ \ 0.2\\\\pmf X \ \  \ \ \ \ \ \ \ 0.1\ \  \ \ \ \ \ \ \ 0.2\ \  \ \ \ \ \ \ \ 0.3\ \  \ \ \ \ \ \ \ 0.2\ \  \ \ \ \ \ \ \ 0.2`

In point b:

\to P(x

In point c:\to P(X+Y

In point d:

\to P(X=0,Y=1)+P(X=0,Y=2)+P(X=0,Y=3)+P(X=0,Y=0)+P(X=1,Y=0)+P(X=2,Y=0)+P(X=3,Y=0)+P(X=4,Y=0) \\\\ \to 0.03+0.04+0.02+0.01+0.02+0.03+0.02+0.02=0.19

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I just had the same question :)

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madreJ [45]

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8 0
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