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blagie [28]
2 years ago
9

You make $10.50 an hour at your part-time job and Andy makes $9.75 an hour at his full-time job. If you work a full week of 40 h

ours how much will you make that week
Mathematics
1 answer:
Marianna [84]2 years ago
7 0
The awnser is $420.00 (10.50 X 40 = 4200)
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Nth term of 70, 100, 130
BlackZzzverrR [31]

Answer:

a1 = 70

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a3 = 130

an = 70 + 30(n - 1)

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Which point is a reflection of (1.5, -4.5) across the x-axis and the y-axis?
Ymorist [56]

Answer:

C. point K

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Compare the values of the underlined digits.
Fantom [35]

To solve this problem, you have to determine the value of the number 3 in both numbers:

6,300 – the number 3 is in the hundreds place so its value is 300

530 – the number 3 is in the tens place so its value is 30

To answer the question, the value of 3 in 6,300 is 10 times the value of 3 in 530.

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3 years ago
Evaluate 90 divided by X to the second power + y
Arlecino [84]

Answer:  =34

=3⋅3⋅3⋅3

=81

For example, 3 to the power of -4:

=3−4

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=0.012346

Step-by-step explanation: the solution is expanded when the base x and exponent n are small enough to fit on the screen. Generally, this feature is available when base x is a positive or negative single digit integer raised to the power of a positive or negative single digit integer. Also, when base x is a positive or negative two digit integer raised to the power of a positive or

negative single digit integer less than 7 and greater than -7.

hopefully this is right :/

4 0
3 years ago
What is the equation of the circle that has its center at -26,120 and passed through the origin
OlgaM077 [116]

well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill

3 0
1 year ago
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