Answer:
Step-by-step explanation:
When we consider Area under arc AC is is representing a quarter as ADBC is a square,
.
Area of quadrant = 
here r= 8 cm
Area under Arc AC= 
Area of white region ABC = Area of square ADBC - Area under Arc AC
![=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2](https://tex.z-dn.net/?f=%3D8%5E2-16%5Cpi%5C%20%5C%20%20%20%20%20%5B%5Ctext%7BArea%20of%20square%7D%20%3D%20sides%5E2%5D%5C%5C%5C%5C%3D%2064-16%5Cpi%5C%20%5C%20%20%3D16%284-%5Cpi%29%5C%20cm%5E2)
Similarly , Area of white region ADC = 
Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

Area of shaded region =
Length of arc AC = 

Perimeter of shaded region = 2(AC) = 
4 is the answer I had the same question
Do distributed property
7/3+3(2/3-1/3)^2
7/3+3×(2/3-1/3)^2
7/3+3×(1/3)^2
7/3×3×1/9
7/3×1/3
7+1/3
8/3 or 2 and 2/3 or 2.66667
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 2, - 6) and (x₂, y₂ ) = (2, - 3) ← 2 points on the line
m =
=
, thus
y =
x + c ← is the partial equation
To find c substitute either ot the 2 points into the partial equation
Using (2, - 3), then
- 3 =
+ c ⇒ c = - 3 -
= - 
y =
x -
← equation of line