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mihalych1998 [28]
3 years ago
9

Which property is not used to simplify the following expression (x+2)×5-7=5 (x+2)-7

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0
Associative
** property I believe.
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Which equation involves a prime quadratic and cannot be solved by factoring? A. x2 + 5x − 4 = 0 B. x2 − x − 6 = 0 C. x2 + 3x − 4
Damm [24]

Answer:

Option A

Step-by-step explanation:

We can try to factorize all the options one by one.

For A:

x^{2} +5x-4\\=> x^{2}+4x+x-4\\=>x(x+4)+1(x-4)

We can see that the quadratic expression cannot be solved by factorization as the factors at the end of factorization are not equal in both brackets. So Option A is the correct answer for the given question.

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When a whole number is multiplied by a decimal smaller than one, what can you conclude about the result?
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Answer:

The answer is D

Step-by-step explanation:

  1. The resulting number is smaller than the original. This is true because if you take 20 times 0.5 it will equal ten. A decimal is pretty much a fraction in another form.

  • The reason why A is false is because if the number isn't being multiplied by 1 then it can't stay the same.
  • The reason why B is false is because that is not true as in the example above, 20 times 0.5, it equaled 10 and not less than one.
  • The reason why C is false is because the the resulting number simply cannot be higher than the original when being multiplied by a decimal smaller than 1.

Hope this helps

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Which expression is equivalent to (8^2)^-4
xz_007 [3.2K]

Answer:

C: \frac{1}{8*8*8*8*8*8*8*8}

Step-by-step explanation:

a^{-n} = \frac{1}{a^n}

Since a = 8^2 :

(8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}

Since n = 4 :

(8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}

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Yy^2 I'm pretty sure is the answer! 
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