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xz_007 [3.2K]
3 years ago
13

How can you solve quadratic equation in one variable using factoring method?​

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
Take a quadratic equation in standard form:
If there exists a sum of two numbers that equal b, whose addends produce a product that equals c. You can rewrite the quadratic as a product of two binomials.


For example take
When thought through throughly, -5 had addends, -2 and -3 that produce 6 when multiplied
Thus, we can rewrite the quadratic as.
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Find the indicated one-sided limit, if it exists:
finlep [7]
The main point which will immediately make it clear is that you have to plug in 2 for x so that you can find the linit. So, using this simple method you will get the <span>-1/4 answer. Hope you will agree with me and find this useful! Regards.</span>
8 0
3 years ago
Integrate ​G(x,y,z)equalsz over the parabolic cylinder yequalszsquared​, 0less than or equalsxless than or equals2​, 0less than
yKpoI14uk [10]

I gather you're supposed to compute the integral of G(x,y,z)=z over a surface S that is the part of the parabolic cylinder y=z^2 with 0\le x\le2 and 0\le z\le\frac{\sqrt{15}}2.

We can parameterize S by

\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k

with the given constraints on x and z. Take the normal vector to S to be

\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k

so that the surface element is

\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz

Then in the integral, we have

\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}

5 0
3 years ago
Help me with this pls pls pls
Lemur [1.5K]
The answer would be the third one, p<319, because the auditorium can seat AT LEAST (<) 320 people, but it would be preferable to contain 319.
5 0
3 years ago
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Write a word problem for (4 x 10) + (5 x 12)=100 Pleaseee tell me it
Natalija [7]
Make the same part of the first one
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3 years ago
BRAINLIEST ANSWER TO FIRST ANSWERER!!!!
mina [271]

Answer:

Option C. tan(B)=2.29

Step-by-step explanation:

we know that

In the right triangle ABC

The tangent of angle B is equal to the opposite side angle B divided by the adjacent side angle B

tan(B)=\frac{AC}{AB}

substitute the values

tan(B)=\frac{16}{7}=2.29

6 0
3 years ago
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