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charle [14.2K]
3 years ago
6

20 POINTS PLEASEEE HELP

Mathematics
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

10. (5,-10) and (2,-4)

11. The maximum height of the ball is 16 feet and it occurs 1 second after the ball is kicked.

Step-by-step explanation:

11. f(x)=-16x^2+32x

0=-16x^2+32x

0=x^2-2x

0=x(x-2)

f(x)=-16^2+32x

f(x)=-16 X (1)^2+32 X (1)

= -16+32

=16

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The sum of three times a number, x, and 12
Marina CMI [18]

Answer:

the number of the x is 5 and the number of the Y is 10

Step-by-step explanation:

school

7 0
3 years ago
PLEASE HELP!!! 20 POINTS!!!! WILL MARK YOU BRAINIEST!!! Two isosceles triangles share the same base. Prove that the medians to t
katovenus [111]

Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

→Case 1.  When vertices A and P are opposite side of Base BC.

In Δ ABD and Δ ACD

AB= AC   [Given]

AD is common.

BD=DC  [median of a triangle divides the side in two equal parts]

Δ ABD ≅Δ ACD [SSS]

∠1=∠2 [CPCT].........................(1)

Similarly, Δ PBD ≅ Δ PCD [By SSS]

∠ 3 = ∠4 [CPCT].................(2)

But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

2 ∠2 + 2∠ 4=360° [using (1) and (2)]

∠2 + ∠ 4=180°

But ,∠2 and ∠ 4 forms a linear pair i.e Point D is common point of intersection of median AD and PD of ΔABC and ΔPBC respectively.

So, point A, D, P lies on a line.

CASE 2.

When ΔABC and ΔPBC lie on same side of Base BC.

In ΔPBD and ΔPCD

PB=PC[given]

PD is common.

BD =DC [Median of a triangle divides the side in two equal parts]

ΔPBD ≅ ΔPCD  [SSS]

∠PDB=∠PDC [CPCT]

Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

∴ P,A,D lie on a line i.e they are collinear.

6 0
2 years ago
Can you help me please with number five
nirvana33 [79]
0.5 gallons
----------
3 0
3 years ago
For what values of m does the graph of y = 3x2 + 7x + m have two x-intercepts
Irina18 [472]

we are given

y=3x^2+7x+m

To find x-intercept means we have to find zeros

and for finding zeros , we will use quadratic formula

and we have it has two x-intercepts

so, it's discriminant must be greater than 0

so, we will find discriminant

D=\sqrt{b^2-4ac}

now, we can compare with

y=ax^2+bx+c

y=3x^2+7x+m

and then we can find a , b and c

a=3,b=7,c=m

now, we can find D

D=\sqrt{7^2-4*3*m}

D=\sqrt{49-12m}

It has two x-intercepts

so,

D=\sqrt{49-12m}>0

now, we can solve for m

49-12m>0

12m

m............Answer

8 0
3 years ago
Read 2 more answers
ADD is to MULTIPLY as SUBTRACT is to what
Rzqust [24]
Divide! If you add three and four, you get seven. Subtracting four from seven, you get three. If you multiply three and four, you get twelve. If you then divide by four, you get back to 3. I hope this helped!
3 0
3 years ago
Read 2 more answers
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