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nalin [4]
4 years ago
13

How to turn 6/3,5/3 & 8/3 into whole fractions

Mathematics
2 answers:
gladu [14]4 years ago
8 0
6/3 = 2
5/3= 1 2/3
8/3= 2 2/3
alex41 [277]4 years ago
3 0
Divide the numerator by the denominator.
For the first one, 6 is the numerator. Divide it by 3 which is the denominator. And then only take the whole number from there.
6/3=2
5/3= 1.something but only take the 1
8/3=2.something but only take the 2
Because the whole fraction only wants the whole numbers.
Thanks :)
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Effectus [21]

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3 years ago
Square root of 2025 by prime factorisation method​<br>Please explain step by step
Mice21 [21]

Answer:

45

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4 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
4 years ago
The volume of a cube is 27 cubic inches. What is the length of one edge of the cube?
yawa3891 [41]

Answer:  3

Step-by-step explanation: 3*3*3=27

7 0
3 years ago
Read 2 more answers
Given the following coordinates complete the glide reflection transformation.​
Romashka [77]

Answer:

A" = (7,-2)

B" = (10,0)

C"=  (12,-3)

Step-by-step explanation:

Given

A = (4,2)

B = (7,0)

C =(9,3)

a: Reflect over x-axis

The rule of this is:

(x,y) \to (x,-y)

So, we have:

A' = (4,-2)

B' = (7,0)

C' = (9,-3)

b: Shift 3 units left

The rule of this is:

(x,y) \to (x+3,y)

So, we have:

A" = (4+3,-2)

A" = (7,-2)

B" = (7+3,0)

B" = (10,0)

C"=  (9+3,-3)

C"=  (12,-3)

4 0
3 years ago
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