Answer:
4
Step-by-step explanation:
-8 + 12 = 4 degrees
9+6(2^2+4)
9+6(4+4)
9+(6)(8)
9+48
=57
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
A 30 hours per year
B 30X(100+20)%=36 per year
1.5 year later is 5.5 years
5.5X36=198 hours
