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nalin [4]
3 years ago
13

What two fractions are equivalent to 3/10

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

6/20 and 9/30

Step-by-step explanation:

Any fraction that can be simplified to 3/10 by dividing the numerator and the denominator is considered equivalent. If you look at the fractions above 6/20 is literally the same thing as 3/10 but I just multiplied the 3 and 10 times 2. As long as you multiply/divide both the numerator and the denominator by the same number the answer you get should be equivalent.

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Hey, can I get some help with this?
algol [13]

Answer:

1.23E7

Step-by-step explanation:

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3 years ago
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I need help on #1 #3 #4
mr_godi [17]

1.) Word form: two hundred thirty-six and seventy-seven thousandths

Expanded notation:   200   + 30   + 6 +     0.0   + 0.07  + 0.007

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3.) tenth: 7.3 hundredth: 7.31 thousandth: 7.305 whole number: 7

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3 years ago
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Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

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Answer:

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2 years ago
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ratelena [41]

Step-by-step explanation:

Pick two points on the line and determine their coordinates

Select one to be (x1, y1) and the other to be (x2, y2)

Finally use the slope intersect equation to calculate the slope:

<em>Formula-</em><em> </em>

<em>y = mx + b </em>

<em></em>

Hope this helps, let me know if you need more information, I'll be glad to help! :)

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