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serg [7]
3 years ago
9

With the beam being held still at a height of 40 m, the crane breaks and the beam falls to the ground. Assuming no air resistanc

e, how much total energy will the beam have just as it hits the ground?
Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.

Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy

TE = 0 + 0

∴ TE = 0

The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
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Divide 6000 by 20
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5 0
3 years ago
What is the percent of 16/25
Lelechka [254]
16/25 = 0.64 = 64%

Another way to do it is to multiply top and bottom by 4
16/25 = (16*4)/(25*4) = 64/100 = 64%

Either way, the answer is 64%
7 0
4 years ago
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The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle
ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is 2w+6.

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

A=w(2w+6)

We can also substitute 40 in for A as it's given in the question.

40 = w(2w+6)

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

40 = 2w^2+6w

We can make the equation simpler by dividing both sides by 2.

20 = w^2+3w

Subtracting both sides by 20 will make the left-hand side 0.

0=w^2+3w-20

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}

w= \frac{-3\pm\sqrt{9+80}}{2}

w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}

Since the second solution results in a negative number, it cannot be the length of w.

w=\frac{-3+\sqrt{89}}{2}\approx3.217

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

l=2(3.217)+6

l=12.434

The length of this rectangle is 12.434 cm.

6 0
2 years ago
Can someone please do this for me or help me pleasee i beg
zlopas [31]
Okay I get some of them, your first one - 1 I disagree with. So we can solve with two points by using a equation y2-y1 over x2-x1. So it's 4-8 over - 3-6 with the numerator being - 4 and the denominator being - 9. Any questions on how to solve for slope with two coordinates.
8 0
4 years ago
Find the volume of the cube
miskamm [114]

Answer:

The volume of cube is 125 cm³.

Step-by-step explanation:

Given that the formule of volume of cube is, V = length×width×height. Cube is a 3D form of square, so the sides of the cube are all the same. You have to substitute 5 into the formula,

Let length be 5 cm,

Let width be 5 cm,

Let height be 5 cm,

Volume = 5×5×5

= 125 cm³

7 0
3 years ago
Read 2 more answers
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