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rodikova [14]
2 years ago
9

Which factor will affect the light-gathering power of a telescope?

Physics
1 answer:
Luden [163]2 years ago
6 0

Answer:a

Explanation:

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A coil with 55 loops has its flux change from 0 Wb to 0.0266 Wb in a certain amount of time, generating 5.22 V of EMF. How much
Eduardwww [97]

Answer:

0.280 s

Explanation:

I set it up as 5.22=(55)(0.0266)/x and then solved for x to be 2.80.

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Miss Hu taught her class what makes night and day on Earth. She could not use the real Sun. She used a light bulb instead. In th
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B. model; it is the model of the sun

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INT Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of 12 pC; these are both very
horsena [70]

Answer:

W = 2.3 10² F_{e}

Explanation:

The force of the weight is

         W = m g

         

let's use the concept of density

         ρ= m / v

the volume of a sphere is

         V = \frac{4}{3} π r³

         V = \frac{4}{3} π (1.0 10⁻³)³

         V = 4.1887 10⁻⁹ m³

the density of water ρ = 1000 kg / m³

          m = ρ V

          m = 1000 4.1887 10⁻⁹

          m = 4.1887 10⁻⁶ kg

therefore the out of gravity is

          W = 4.1887 10⁻⁶ 9.8

          W = 41.05 10⁻⁶ N

now let's look for the electric force

           F_e = q E

           F_e = 12 10⁻¹² 15000

           F_e = 1.8 10⁻⁷ N

         

the relationship between these two quantities is

          \frac{W}{F_e} = 41.05 10⁻⁶ / 1.8 10⁻⁷

           \frac{W}{F_e} = 2,281 10²

             

             W = 2.3 10² F_{e}

therefore the weight of the drop is much greater than the electric force

3 0
2 years ago
Kinetic or potential energy
chubhunter [2.5K]
Potential, if the bow is released kinetic
3 0
2 years ago
A small sphere is hung by a string from the ceiling of a van. When the van is stationary, the sphere hangs vertically. However,
olganol [36]

Answer with Explanation:

We are given that

String makes an angle w.r.t  vertical=\theta=

a.We have to derive an expression for the magnitude of the acceleration of the van in terms of the angle \theta and magnitude g of the acceleration due to gravity.

According to newton's second law

T sin\theta=ma

Tcos\theta=mg

\frac{Tsin\theta}{Tcos\theta}=\frac{ma}{mg}

tan\theta=\frac{a}{g}

a=gtan\theta

b.\theta=10^{\circ}

g=9.8 m/s^2

a=9.8\times tan10^{\circ}=1.73 m/s^2

c.Velocity=Constant

We have to find the angle \theta

a=0

0=9.8tan\theta

tan\theta=0

tan\theta=tan0

\theta=0^{\circ}

3 0
2 years ago
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