Distance = 0.5 x g x t^2 where g is the gravitational force and t is the time required to cover the mentioned distance.
we have g = 9.8 m/sec^2 and distance = 16 cm = 0.16 m
From the above mentioned equation:
t = (2s / g)^0.5
Substituting with the givens, we can calculate t as follows:
t = [(2 x 0.16) / 9.8]^0.5 = 0.1807 seconds
Explanation:
entropy is the randomness or disorder of a system right?
we know gases have negligible forces of attraction hence the particle move in an uphazard manner hence there great disorder as compared to liquid with low force of attraction low kinetic energy but in solid particles are held by strong intermolecular forces in fixed position where kinetic energy is low and order is greater here
Answer:
Chemical energy to Electrical energy to Light energy
Explanation:
- Chemical energy; This is the energy stored in the battery.
- Electrical energy; This is the energy transformed by the battery and sent through the connecting wires to the lightbulb
- Light energy; When the electrical energy gets to the light bulb ,the light bulb converts it to light energy. Which is seen when the light bulb is turned on.
Answer:
The answer to the question is
Its maximum speed is 1.54 m/s
Explanation:
Work done = Kinetic energy
0.5·m·v² = 0.5·k·x²
Where
m = mass
v = velocity
k = spring constant
x = extension of the spring
We note that Force F is given by
F = m·a
Where
a = acceleration due to gravity
= 0.153×9.8 = 1.4994 N
Equating the work done by the force to the work done on the spring gives
Work done = Force × Distance = 1.4994×x = 0.5×k÷x² = 0.5×24.7×x²
x = 1.4994÷12.35 = 0.121 m
Substituting the value of x into the equation below gives
0.5·m·v² = 0.5·k·x²
0.5×0.153×v² = 12.35×0.121²
v² = 0.182÷0.0765 = 2.379
v = 1.54 m/s
Answer:
E = 169.34 J
Explanation:
First, we need to find the frictional force between the back tire and the road. For that purpose, we use the following formula:
f = μR = μW
f = μmg
where,
f = frictional force = ?
μ = coefficient of friction between tire and road = 0.8
g = 9.8 m/s²
m = mass supported by back tire = (0.5)(90 kg) = 45 kg
Therefore,
f = (0.8)(45 kg)(9.8 m/s²)
f = 352.8 N
Now, for the heat energy we use the formula of work. Because, thermal energy will be equal to work done by frictional force:
E = W = fd
where,
E = Thermal Energy = ?
f = frictional force = 352.8 N
d = displacement = 48 cm = 0.48 m
Therefore,
E = (352.8 N)(0.48 m)
<u>E = 169.34 J</u>