Increase in wavelength will cause decrease in frequency. When wavelength doubles, the frequency of the wave will reduce to half of its value.
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WAVE SPEED</h3>
The wave speed is the product of wave frequency and its wavelength.
v = f⋅λ
For example, if a wave has a frequency of 120 Hz and a wavelength of 5m, it would have a speed of 600 m/s.
if the wavelength is increased to 10m but the speed stays the same at 600 m/s. That is,
λ = 10m
v = 600 m/s
v = f⋅λ
Substitute f and v into the formula
600 = 10f
f = 600 / 10
f = 60 m
The frequency of the wave is reduced to half of its value.
Learn more about wave speed here: brainly.com/question/2847127
Answer:
Current sensitivity voltage sensitivity of a galvanometer depend is on a number of turns, coil area, restoring force per unit twist and megnetic filed.
<span>Car B has a greater momentum than car A.
Since, momentum = mass * velocity
mass of both car A and B is same, velocity of B is greater than A.
So, momentum of car B = 1200 * 25 = 30,000 kg-km/h is greater than </span>momentum of car A = 1200 * 22 = 26400 kg-km/h
One atom on nitrogen because there isn’t a number directly after it’s the 3 signifies that there is three groups of those atoms as a total
Answer:
Explanation:
The resistance of a wire is given by:
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
1) The first wire has length L and cross-sectional area A. So, its resistance is:
2) The second wire has length twice the first one: 2L, and same thickness, A. So its resistance is
3) The third wire has length L (as the first one), but twice cross sectional area, 2A. So, its resistance is
By comparing the three expressions, we find
So, this is the ranking of the wire from most current (least resistance) to least current (most resistance).
