What are the vertex and axis of symmetry of the parabola y=3x^2-24x+38?
1 answer:
Answer:
see explanation
Step-by-step explanation:
given a parabola in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex which is also the axis of symmetry is
= -
y = 3x² - 24x + 38 is in standard form
with a = 3, b = - 24 and c = 38, hence
= -
= 4
Substitute x = 4 into the equation for corresponding y- coordinate
y = 3(4)² - 24(4) + 38 = 48 - 96 + 38 = - 10
vertex = (4, - 10)
equation of axis of symmetry is x = 4
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