Answer:
The six trig ratios at 3pi/2 are:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2) (undefined)
csc(3pi/2)=-1
sec(3pi/2) (undefined)
cot(3pi/2)=0
Step-by-step explanation:
If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.
cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.
3pi/2 satisfies the given constraint.
The six trig ratios are therefore:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2)=-1/0 (undefined)
Reciprocal values:
csc(3pi/2)=-1
sec(3pi/2) undefined since cos(3pi/2)=0
cot(3pi/2)=0/-1=0
2 of the 8 slices of pie A were sold (2/8)
3 of the 6 slices of pie B were sold (3/6)
Both of these fractions can be simplified
2/8 --> 1/4
3/6 --> 1/2
In order to add these two fractions, they must have a common denominator. This can be accomplished by multiplying the second fraction by 2
1/2 --> 2/4
Now we can add the two
1/4 + 2/4 = 3/4
Therefore 3/4 of the pie has been sold. In order to find out how much remains, we must subtract the amount that has been sold from the original amount of pie (2)
2 - 3/4 = 1 1/4 = 1.25
Answer:
x= 376
Step-by-step explanation:
100/25=4
94*4=376
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time.
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
