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Marrrta [24]
3 years ago
11

What is the greatest common factor of 15n^5, 30n^3, and 45n^2?

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

the greatest common factor is  45n^2

Step-by-step explanation:

Mama L [17]3 years ago
4 0

Answer:15n^2

Step-by-step explanation: The greatest common factor of 15,30, and 45 is 15. The greatest common factor of n^5, n^3, and n^2 is n^2.

so together is 15n^2

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Lera25 [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago
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Two system of equations 2y =14-2x and y=-x + 7 is graphed. What is the solution to the system of equations
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<h2>Answer:</h2>

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A prism has length 2 feet, width 3 feet, and height 5 feet. What is the volume in cubic INCHES?
kolbaska11 [484]
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3 years ago
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The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the
maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that a = 0.95, b = 1.05

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

P(X > x) = 0.9

So

\frac{1.05 - x}{1.05 - 0.95} = 0.9

1.05 - x = 0.9*0.1

x = 1.05 - 0.9*0.1

x = 0.96

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0
3 years ago
50 POINTS FOR THIS
sergejj [24]

Answer:

i have the same problem as you, i need help as well

Step-by-step explanation:

6 0
2 years ago
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