Question

a person standing near the top of the Eiffel tower(approximately 300.6 meters) notices a car wreck some distance from the tower. If the angle of depression from the person's eyes to the wreck is 32°, approximately how far away is the accident from the base of the tower? ​

Answer 1

Answer:

481.06

Step-by-step explanation:

Let's visualise this case in a right angled triangle.

Height = 300.6 m

Angle of depression = Angle of elevation = 32°

So,

$\sin(32) = \frac{300.6}{hypotenuse}$

$= > 0.5299192642 = \frac{300.6}{hypotenuse}$

$= > hypotenuse = \frac{300.6} {0.5299192642 }$

$= 567.2562224244 m$

Hypotenuse = Line of sight = 567.25 m

Also,

$\cos(32) = \frac{base}{567.2562224244}$

$= > 0.8480480962 = \frac{base}{567.2562224244}$

$= > base = 0.8480480962 \times 567.2562224244 = 481.0605594599$

Hence Base = Distance between the spot of accident & the base of the tower = 481.06 m