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svlad2 [7]
3 years ago
11

What is the solution to the system of equations below? y=2/5x-3 and x=-10

Mathematics
2 answers:
Vinil7 [7]3 years ago
6 0

Answer:

the solution (x,y) for the system of equation  is (-10, -7)

Step-by-step explanation:

y=2/5x-3 and x=-10

y=\frac{2}{5} x-3

Given x=-10

Replace x with -10 in our equation and find out y

y=\frac{2}{5} x-3

y=\frac{2}{5}(-10)-3

y=-4-3=-7

When x=-10 the value of y is -7

So the solution (x,y) for the system of equation  is (-10, -7)

mojhsa [17]3 years ago
4 0

Answer:

The solution is (-10,-7)

Step-by-step explanation:

y=2/5x-3 and x=-10

We know x = -10

Substitute the second equation into the first equation to find y

y = 2/5 (-10) -3

y = -4 -3

y = -7

The solution is (-10,-7)

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iragen [17]

Answer:

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\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

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The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

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<u>Final Solution</u>

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\sf (-3, \infty)

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