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Andrei [34K]
3 years ago
9

What are pixels? A. Objects that are part of a particle system B. Tiny colored dots that make up images and text on a computer s

creen C. Very small Active objects D. Objects that are inactivated when they're too far outside the play area
Computers and Technology
1 answer:
vovikov84 [41]3 years ago
6 0

i would say B is the correct answer :)

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Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
PLEASE HELP!!!!!! ASAP
NNADVOKAT [17]

Answer:

use a wizard or use a design view

Explanation:

i took the test

4 0
3 years ago
Read 2 more answers
In a linked chain implementation of a queue, the performance of the enqueue operation
alexdok [17]

Answer:

A.O(1)

Explanation:

In the implementation of queue by using linked chain the performance of  the enqueue operation is O(1).We have to  maintain  two pointers one  head and the other tailand  for  enqueue operation  we have to insert element  to the next of the tail and then  make that element  tail.Which takes O(1) time.

4 0
3 years ago
Get user input as a boolean and store it in the variable tallEnough. Also, get user input as a boolean and store it in the varia
frozen [14]

Answer:

I will code in JAVA.

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

 

boolean tallEnough;

boolean oldEnough;

Scanner input = new Scanner(System.in);

tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>

oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>

   if(tallEnough && oldEnough){

   System.out.print(true);

   } else {

   System.out.print(false);

   }

}

}

Explanation:

First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.

In the if-else statement checks if both variables are true, then prints true. Another case prints always false.

8 0
3 years ago
Which of the following statements about the continue statement is true?
kotykmax [81]

Answer:

Option (d)

Explanation:

  • The Continue statement is used inside the looping statements.
  • When a Continue statement is encountered inside the loop, it stops executing the current iteration ( it skips the next steps in the current iteration) and goes to the next iteration.
  • It then continues to execute the loop for the next iteration.
  • The continue statement can be used in all the looping structures ( for loop, while loop, do while loop ).
  • The syntax for continue statement is " continue; "
  • Options (a),(b),(c) are wrong options.
  • Option (d) is correct option.
8 0
3 years ago
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