Answer:
The correct loop is as follows:
for year in range(starting_tuitionYear, ending_tuitionYear, increment):
tuition = startingTuition + rate * startingTuition
startingTuition = tuition
print('Tuition for the year of ' + str(year)+ ' is ' + str(tuition));
Explanation:
Required
The correction to the attached program
Some variables are not needed; so, I've removed the redundant variables.
The main error in the program is in the loop;
After the tuition for each year has been calculated, the startTuition of the next year must be set to the current tuition
<em>See attachment for complete program</em>
Answer:
B
Explanation:
Every HTML document must begin with a declaration of what the document is going to be about.
1. Start up Open Office.Org.
2. Click on File >> New >> Labels.
3. In the label dialog box, click on the brand box. This will allow you to choose the type of paper that you use.
4. Select the type of document that you want. The usual standard is Avery, but feel free to explore and discover what you like.
5. Select if you want a single label, a document, and any other options. Some of the things you might want to do are:
- Create a variety of labels for folders or drawers
- Create a sheet of address labels
- Create decorative labels
6. Click New Document. Here, you see a sheet of blank labels.
7. Create the type of format/placement that you want for your labels. Once you are happy with it, copy it to the rest of the labels.
8. Fill your labels with necessary information.
9. Print them out.
Explanation:
can u suggest a title about quarantine
ex: My quarantine life
Answer:
a) 4 processes
b) 2 resources
c) R1: 2 instances
R2: 2 instances
d) R2
e) R1
f) R1
g) No resource
h) R1
i) R2
j) R2
k) No
l)No deadlock
Explanation:
You need to know that the resources that are required by the processes for completion are shown by the request edge and the resources allocated are shown by the allocation edge. And thus, we can find what resources are allocated to the process, and required for the completion accordingly. And here again, the cycle is created, and hence deadlock may or may not occur. However, we see that resources have multiple instances and get freed on time. And hence, deadlock does not occur.
Like,
P4 uses R2 and free one instance of R2.
P3 then uses one instance of R2 and free R2.
P3 then uses one instance of R3 and free R3.
P1 uses one instance of R1 and free R1 one instance
P1 then uses R2 and free R2.
P2 uses R1 and free R1.
Hence, all the processes are complete and deadlock does not occur.
