Answer:
B. #
Explanation:
Every preprocessing directive must begin with the # character.
For example:
#define : Used to define a macro
#ifndef : Conditional evaluation of macro
#include : Used to include other preprocessor header file as part of the code
As we can see each of the directives begins with the # character. This is a signal to the preprocessor to interpret the subsequent keyword as a directive.
Answer:
(B) Home
Explanation:
Echo is an Amazon product.
Home is a smart speaker developed by Google.
Cortana is a product of Microsoft.
HomePod is developed by Apple.
If Henry wants to be connected to his Google account, you would recommend him to buy Home, because it is a Google product.
Answer:
A. true
Explanation:
Based on the information provided within the question it can be said that the statement is completely true. This is because, traffic-monitoring applications have the main function of monitoring and analyzing the flow of traffic of one or various different items. Which can be applied to the business involving utility, infrastructure, and environmental services by monitoring the specific items regarding each business. Therefore making sure that enough product is entering or leaving each business as it is suppose to. As well as providing stock analysis and defective product alerts.
Answer:
The solution code is written in Python 3:
- def modifyList(listNumber):
- posCount = 0
- negCount = 0
-
- for x in listNumber:
- if x > 0:
- posCount += 1
- else:
- negCount += 1
-
- if(posCount == len(listNumber)):
- listNumber.append(max(listNumber))
-
- if(negCount == len(listNumber)):
- listNumber.append(min(listNumber))
-
- print(listNumber)
-
- modifyList([-1,-99,-81])
- modifyList([1,99,8])
- modifyList([-1,99,-81])
Explanation:
The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).
To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).
If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).
If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.
At last we can print the listNumber (Line 17).
If we test our function using the three sets of input list, we shall get the following results:
[-1, -99, -81, -99]
[1, 99, 8, 99]
[-1, 99, -81]
