Use the expression to complete the table.<br>**Look above for the picture.

Pls help me with this

Free_Kalibri [48]

Answer:

$\boxed{\sf \frac{15}{22} }$

Step-by-step explanation:

The radius of the circle is 7 cm.

The two legs of the triangles are 7cm as well.

Area of a trinagle is ( base × height )/2.

$\frac{7 \times 7}{2} =24.5$

Multiply the value by 2 since there are two triangles.

$24.5 \times 2 = 49$

Calculate the area of the circle.

$\pi r^2$

The radius is given.

$\pi (7)^2$

Take $\pi$ as $\frac{22}{7}$

$49(\frac{22}{7} )$

$=154$

Subtract the area of the two triangles from the area of the whole circle.

$154-49=105$

The area of the shaded part is 105 cm². The total area of the shape is 154cm².

$\frac{105}{154} =\frac{15}{22}$

5 0

3 years ago

Describe the piecewise function below by evaluating the function for given values of the domain

tekilochka [14]

We have a piecewise function.
Therefore, to find the function, we must evaluate each domain separately.
We have then:

For $x \leq -2$ :
The function for this domain is:
$y = -3
$

For $-2 \ \textless \ x \leq 2$ :
The function for this domain is:
$y = mx + b
$
Where,
$b = -3

 m = (y2 - y1) / (x2 - x1)

 m = (1 - (-7)) / (2 - (-2))$
$m = (1 + 7) / (2 + 2)

 m = 8/4

 m = 2$
Substituting:
$y = 2x - 3
$

For $x\ \textgreater \ 2$ :
The function for this domain is:
$y = 5$

4 0

3 years ago

Which is the completely factored form of 12x3 – 60x2 + 4x – 20?

Bas_tet [7]

Answer:

2 ( 6 x^ 3 − 30 x ^2 + 2 x − 1 )

Step-by-step explanation:

6 0

3 years ago

Complete the equation of the line through (3, -1) and (4, 7)

nikitadnepr [17]

Answer:

y = 8x -25

Step-by-step explanation:

The two-point form of the equation of a line can be used.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (7-(-1))/(4-3)(x -3) +(-1)

y = 8(x -3) -1

y = 8x -25 . . . . slope-intercept form of the equation

_____

We don't know what you're starting with, so we don't know how to "complete the equation." Perhaps the above equation is sufficient for the task.

4 0

3 years ago

Please solve this<br><img src="https://tex.z-dn.net/?f=%20%7Cx%20%5E%7B2%7D%20%2B%203x%20-%201%20%7C%20%20%3C%203" id="TexFormul

klasskru [66]

$\bf |x^2+3x-1|\ \textless \ 3\implies 
\begin{cases}
+(x^2+3x-1)\ \textless \ 3\\\\
-(x^2+3x-1)\ \textless \ 3
\end{cases}\\\\
-------------------------------\\\\
x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0
\\\\\\
x\ \textless \ 
\begin{cases}
-4\\
1
\end{cases}\\\\
-------------------------------\\\\
-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3
\\\\\\
x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ 
\begin{cases}
-2\\
-1
\end{cases}$

8 0

3 years ago

Use the expression to complete the table.**Look above for the picture.​

Use the expression to complete the table.**Look above for the picture.