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lana [24]
3 years ago
9

Can someone please help me

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Hi!

First, let's solve for d.

To get 18y^{6}, you need to add ³ + ³. So d has to equal ³.

(cy^3)(9y^3) = 18y^{6}

Now solve for c.

Because 9 * 2 = 18, c has to equal 2.

(2y^3)(9y^3) = 18y^{6}

The answer is

c = 2

d = 3

Hope this helps! :)

-Peredhel

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Answer:

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Step-by-step explanation:

It is given that,

V = bdt i.e. V is equal to the product of b, d and t

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Dividing both sides of the given expression by bt

So,

\dfrac{V}{bt}=\dfrac{bdt}{bt}\\\\d=\dfrac{V}{bt},\ \text{bt in both denominator and numerator cancel out}

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3 years ago
PLZ CHECK MY ANSWER. Round your answer to the nearest tenth.
Umnica [9.8K]

Answer:

D. 70.34 cm^2

Step-by-step explanation:

Area of sector of a circle is given as θ/360*πr²

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4 0
4 years ago
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anastassius [24]
6; because they are an equal distance apart
7 0
3 years ago
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What is the probability of picking a 7 from a standard deck of 52 cards?
BARSIC [14]

Answer:

(c)- 4/13

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8 0
3 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

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a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
3 years ago
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