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4 years ago

Evaluate the expression described below if the number is 4. The difference between a number squared and the number.

1 answer:

3 0

Hello,

$x^2-x=4\\
x^2-x-4=0\\
\Delta=1^2-4*(-4)=17\\
x= \dfrac{1+ \sqrt{17} }{2} \\
or\\
x= \dfrac{1- \sqrt{17} }{2} \\
$

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3 years ago

Suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120. What is the length of t

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Answer:

A, B, C, E

Step-by-step explanation:

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<u>Correct statements, reasons:</u>

A - adjacent angles are supplementary
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<u>Incorrect statements, reasons:</u>

D - opposite angles are congruent, but not supplementary
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3 years ago

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LenaWriter [7]

(a) Slope is rise over run, or change in y over change in x.

1 -> 3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{4 - -8}{-1 - -5} = \frac{4 + 8}{-1 +5}= \frac{12}{4} =\frac{12}{4}$ )

2 -> 3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{1 - 7}{0 - 2} = \frac{-6}{- 2} =\frac{6}{2}$ )

3 -> -1/3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-7 - -3}{6 - -6}= \frac{-7+3}{6+6}=\frac{-4}{12}=-\frac{1}{3}$ )

(b) If a line is parallel, the slopes will be the same. If they are perpendicular, the slopes will be are negative reciprocals of one another. If they are neither, then their slopes don't match up in any way.

1 & 2 -> Parallel

1 & 3 -> Perpendicular

2 & 3 -> Perpendicular

Note - Since 1 & 2 are parallel, then both 1 and 2 will be perpendicular to 3!

Have a nice day!

If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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