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Dmitrij [34]
3 years ago
9

Suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120. What is the length of t

he third side of the triangle? A. 33.60 B. 53 C. 58.04 D. 47.43
Mathematics
1 answer:
Naily [24]3 years ago
6 0
You would need to use the Law of Cosines.

c^2=a^2+b^2-2abcosC

In this case:

c=√(32^2+35^2-2*32*35cos120)

c≈58.04 units
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