Question

Suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120. What is the length of the third side of the triangle? A. 33.60 B. 53 C. 58.04 D. 47.43

Answer 1

You would need to use the Law of Cosines.

c^2=a^2+b^2-2abcosC

In this case:

c=√(32^2+35^2-2*32*35cos120)

c≈58.04 units