Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
<em />
<u>c.)44 kilometers</u>
Answer:
Solution given:
let
length =L
and
Area =A
Now
we have
Area [A]=1936 square kilometers
now
As we know that
Area of square :length *length
A=l*l
A=l²
Substituting value of A
1936=l²
doing square root on both side

we get
l=
l=2*2*11
l=44 kilometers
So
<u>the length of one side of a </u><u>square</u><u> </u><u>is</u><u> </u><u>4</u><u>4</u><u> </u><u>kilometers</u><u>.</u><u />
Answer:
Sue
Step-by-step explanation:
34/2= 17 which is the highest out of them all.