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lapo4ka [179]
3 years ago
13

If you flip three fair coins what is the probability that the two first flips will both be heads, and the third flip will be eit

her heads or tales?
Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

The probability that a coin flip is a head or a tail is 0.5. The probability that a coin flip is either a head or a tail is 1. The probability that a three-coin-flip is two heads and a head or a tail is 0.25.

Step-by-step explanation:

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Matthew is four years younger than his brother Kevin,when Matthew was 7,how old was his brother
cestrela7 [59]

Answer:

Kevin was eleven years old.

Step-by-step explanation:

7+4=11, since the question says Matthew is younger by four years.

8 0
3 years ago
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Simplify the expression. Write your answer as a power. 5^8 x 5^5/5^4 x 5^3
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

5^5/5^4 = 5^(5-4) = 5

5^8 * 5 * 5^3 = 5^(8+1+3) = 5^12

7 0
3 years ago
4 sailboats to 12 motorboats
lukranit [14]

Answer:

4:12

Step-by-step explanation:

I think you asked for a ratio?

8 0
3 years ago
1. (5pt) In a recent New York City marathon, 25,221 men finished and 253 dropped out. Also,
gladu [14]

Answer:

(a) Explained below.

(b) The 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

Step-by-step explanation:

The information provided is:

n (Men who finished the marathon) = 25,221

n (Women who finished the marathon) = 12,883

Compute the proportion of men and women who finished the marathon as follows:

\hat p_{1}=\frac{25221}{25221 +253}=0.99\\\\\hat p_{2}=\frac{12883 }{12883+163}=0.988

The combined proportion is:

\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}\\\\=\frac{25221+12883}{38520}\\\\=0.989

(a)

The hypothesis is:

<em>H</em>₀: The rate of those who finish the marathon is the same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.

<em>Hₐ</em>: The rate of those who finish the marathon is not same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.

Compute the test statistic as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)\cdot [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.99-0.988}{\sqrt{0.989(1-0.989)\times[\frac{1}{25474}+\frac{1}{13046}]}}\\\\=1.78

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z>1.78)\\\\=2\times 0.03754\\\\=0.07508\\\\\approx 0.075

The <em>p</em>-value of the test is more than the significance level. The null hypothesis was failed to be rejected.

Thus, concluding that the rate of those who finish is the same for men and women.

(b)

Compute the 99% confidence interval for the difference between proportions as follows:

The critical value of <em>z</em> for 99% confidence level is 2.58.

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.99-0.988)\pm 2.58\times\sqrt{\frac{0.99(1-0.99)}{25474}+\frac{0.988(1-0.988)}{13046}}\\\\=0.002\pm 0.00294\\\\=(-0.00094, 0.00494)\\\\

Thu, the 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

6 0
3 years ago
Kenji buys 3 yards of fabric for 7.47.Then he realizes that he needs 2 more yards.How much will the extra fabric cost
AleksAgata [21]

7.47/3 = 2.49

1 yard = 2.49

2 x 2.49 =

4.98 is how much it will cost for 2 extra yards

5 0
4 years ago
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