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inessss [21]
3 years ago
12

Write the domain AND range of the following graph.

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer:

Domain: (-∞,∞), Range: [2,∞)

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In a game, a participant is given three attempts to hit a ball. On each try, she either scores a hit, H, or a miss, M. The game
Sidana [21]

Answer:

chancing for wining is 54%.

Step-by-step explanation:

possible outcomes can be given as

HHH *

HHM *

HMH

MHH *

HMM

MHM

MMH

MMM

Out of those, only 3 will have the participant win the game:

HHH, HHM, MHH.

Probability (HHH) + Probability (HHM) + Probability (MHH)

since attempts are independant.

Probability (HHH) = 0.9 *0.4 *0.9 = 0.324

Probability (HHM) = 0.9 *0.4 *0.3 = 0.108

Probability (MHH) = 0.3 *0.4 *0.9 = 0.108

Add them up and get  = (0.324+ 0.108+0.108) = 0.54

hence, chancing for wining is 54%.

3 0
3 years ago
Factor: a^2 m + 5am – 30m
DIA [1.3K]
I am gonna go with C.
6 0
4 years ago
_____ divided by 2/3=3/4<br>​
Lina20 [59]

Answer:

\frac{1}{2}

Step-by-step explanation:

Multiply the quotient \frac{3}{4} by the divisor \frac{2}{3} for the dividend, that is

\frac{3}{4} × \frac{2}{3}

Cancel the 3 on the numerator/ denominator

= \frac{1}{4} × \frac{2}{1} = \frac{2}{4} = \frac{1}{2}

4 0
3 years ago
TELL ME THE POINTS TO GRAPH TO BE MARKED BRAINLIEST
scoundrel [369]
Solve by elimination
multiply top by -1

-2x + y = -4
    x - y  = -2

-x = -6..............so x = 6

2(6) - y = 4
12-y = 4
-8 = -y
so y = 8

(-6,8)

6 0
4 years ago
Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
4 years ago
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