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tensa zangetsu [6.8K]
3 years ago
13

Write an equation that is parallel to the line 4x - y = 2 and passes through the point (-2, 3)

Mathematics
1 answer:
sergeinik [125]3 years ago
7 0
We can start from the given line's coefficients and translate the line from the origin to the given point.
  4(x -(-2)) -(y -3) = 0
  4x +8 -y +3 = 0

The equation of the desired line is ...
  4x -y = -11

_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
  a(x-h) +b(y-k) = 0
which is completely equivalent to
  ax +by = ah +bk

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Can anyone help me with this problem by factoring and list the steps please
jok3333 [9.3K]

Answer:

m=2, m=0

-ˋˏ✄┈┈┈┈┈┈┈┈┈┈┈┈┈

20m^2-40m=0

<u>Use quadratic formula:-</u>

᠃ ⚘᠂ ⚘ ˚ ⚘ ᠂ ⚘ ᠃

m_1,_2=\frac{-(-40) -+\sqrt{x} (-40)^2-4*20*0}{2*20}

\sqrt{(-40)^2-4*20*0}=40

m_1,_2=\frac{-(-40)-,+40}{2*20}

m_1=\frac{-(-40)+40}{2*20},m_1=\frac{-(-40)-40}{2*20}

m=\frac{-(-40)+40}{2*20}:2

m=\frac{-(-40)-40}{2*20}:0

m=2, m=0

˱   ┈  ┈  ┈  ┈   ˲

hope it helps...

have a great day!!

6 0
3 years ago
I need help figuring out how to do this.
MrRa [10]
The answer will be letter "B" you take 450 times it by 4.29
and u get 1,930.50
7 0
3 years ago
Read 2 more answers
How is a one-degree angle helpful classifying angles?
faltersainse [42]
It can give you a pretty good idea of how many degrees everything is. for example if something was 13degrees, you would be able to make an estimate because you know how much one degree is.
6 0
3 years ago
Answer in standard form PLEASE.
matrenka [14]

0.9 x 10^4

Let’s break this down into steps.

So to start off with, you need to do 4.5/5 which = 0.9.

Now we can deal with the indices. 10^-3 / 10^-7 means we have to subtract them. Therefore, -3 - -7 = 4. Altogether, we have 0.9 x 10^4

The question states we should leave our answer in standard form.

So our answer is 0.9 x 10^4.
8 0
3 years ago
A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin
maks197457 [2]

Answer:

(a) \sum x_i=56.68 and \sum x_i^2=197.46

(b) The sample variance is s^2=0.530 and the sample standard deviation is s=0.728

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68

and the sum of their squares is

\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46

(b)

The sample variance, denoted by s^2, is given by

s^2=\frac{S_{xx}}{n-1}

where S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}

Applying the above formula we get that

S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482

s^2=\frac{8.482}{17-1}=0.530

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

s=\sqrt{s^2}

Applying the above formula we get that

s=\sqrt{0.530}=0.728

3 0
3 years ago
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