Write an equation that is parallel to the line 4x - y = 2 and passes through the point (-2, 3)
1 answer:
We can start from the given line's coefficients and translate the line from the origin to the given point.
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
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For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
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Answer:
Step-by-step explanation:
We are given the function:
Remember that by the definition of absolute value:
Our absolute value is:
First, we will find when it becomes 0. Set the equation equal to 0:
Solve for <em>x: </em>
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So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.
For all values less than <em>x </em>= 5/2, 2x - 5 is negative.
Therefore (the positive case go above, and the negative case go below):
Finally, we can add a three:
Simplify if desired: