Hello there,
The <em>answer is </em>A' (-3,2).
<h3>Step-by-step explanation:-</h3>
From the image shown on the xy-plane, the coordinate of point A is at (3,-2).
The rule for rotation by 180° about the origin is (x,y)→(-x, -y), where (x,y) is the coordinate of image and (-x, -y) is the coordinate of the resulting pre-image.
Given the coordinate point A(3,-2), if this coordinate is rotated 180°, the resulting point A' will be located at (-3,-(-2)) = (-3,2).
Therefore, the answer will be <u>A'(-3,2)</u>
✍️ <em>by </em><em>Benjemin</em> ☺️
Let's make it an expression.
Three half's= 3/2 Plus= + one fifth= 1/5
We need to turn 3/2 and 1/5 so that they have the same denominator. Let's use 10.
3/2→15/10 1/5→2/10
15/10+2/10=17/10=1 7/10
So, three half's plus one fifth is 1 7/10.
10x^4y^4+2x^6-15y^6-3x^2y^2
(In the picture, QRST looks like a rhombus, so I will assume that it is a rhombus.)
In a rhombus, opposite angles are congruent based on the alternate interior angle theorem. In other words, R and T along with Q and S are both alternate interior angle pairs.
(You can actually test this by printing out a rhombus, cutting out the angles, and matching up the opposite ones.)
We know that Q is equal to 4x + 10, but we need to solve for x. Since Q and S are congruent, we can set them equal to each other:
1) 4x + 10 = 5x - 3
2) 4x + 13 = 5x
3) 5x = 4x + 13
4) x = 13
Now let's plug 13 in for Q:
5) 4(13) + 10 = 52+10 = 62
I got m<Q = 62 degrees. Hope this helps!