What are the roots of the equation x^2+4x-5=f(x)

Mathematics

1 answer:

enyata [817]3 years ago

3 0

Answer:

The roots are -5, 1.

Step-by-step explanation:

$f(x) = x^2 + 4x - 5$

The roots of a function are also the Ox intercepts, so basically we're finding when is the function equal to '0'.

$x^2 + 4x - 5 = 0\\(x-1)(x+5) = 0\\x_1 = 1, x_2 = -5$

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