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Flura [38]
3 years ago
10

What are the roots of the equation x^2+4x-5=f(x)

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Answer:

The roots are -5, 1.

Step-by-step explanation:

f(x) = x^2 + 4x - 5

The roots of a function are also the Ox intercepts, so basically we're finding when is the function equal to '0'.

x^2 + 4x - 5 = 0\\(x-1)(x+5) = 0\\x_1 = 1, x_2 = -5

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Elan Coil [88]

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

\frac{part}{whole} = \frac{percent}{100}

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

\frac{77}{x} = \frac{15.4}{100}

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

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3 years ago
The measure of each exterior angle of a regular 30-gon is
dezoksy [38]

Answer:

12°

Step-by-step explanation:

So, for your 30-gon, the interior angles total up to (30-2) * 180 = 5040.   Each interior angle is that total divided by the number of interior angles, or 5040/30 = 168º:

 

<u>The measure of each exterior angle is the total divided by the number of angles, or 360/30 = 12º.</u>

4 0
3 years ago
Morton made 36 out of 48 free throws last season. What percent of his free throws did Morton make. Help!!! T-T
blondinia [14]

75 % free throws are made by Morton

<em><u>Solution:</u></em>

Given that Morton made 36 out of 48 free throws last season

To find: Percent of free throws made by Morton

From given statement,

total number of throws = 48

throws made by morton = 36

<em><u>Thus the percent of free throws made by Morton is given as:</u></em>

percent = \frac{\text{number of throws made}}{\text{total number of throws}} \times 100

Substituting the values, we get

percent = \frac{36}{48} \times 100\\\\percent = 0.75 \times 100 = 75 %

Thus 75 % of his free throws are made by Morton

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