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sertanlavr [38]
2 years ago
7

Someone please help me with this

Mathematics
2 answers:
grin007 [14]2 years ago
5 0
The answer above is correct, except your slope should be negative. So the correct answer should be

y = -3/4 -3
Lynna [10]2 years ago
3 0

Answer:

Step-by-step explanation:

3/4x + -3

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In order to estimate the height of a building, two students stand at a certain distance from the building at street level. from
enyata [817]
Let h represent the height of the building. Then the difference between the two angle measurement locations is
.. h/tan(39°) -h/tan(50°) = 300 ft
.. h = (300 ft)/(1/tan(39°) -1/tan(50°))
.. h ≈ 758 ft

The height of the building is about 758 feet.
4 0
3 years ago
the cozy cat shop has 3 calico cats for every gray cat. If they have nine calico cats available, how vany gray cats do they have
Cerrena [4.2K]
Set up as for portion with X as unknown number of gray cats. So 1/3=x/9. Cross multiply. 3X=9. Divide both sides by 3. X=3.
3 0
3 years ago
Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k​
masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

2

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

We find the discriminant,

D=(1-k)^2-4(1)(k-3)D=(1−k)

2

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

2

−2k−4k+12

D=k^2-6k+13D=k

2

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0
3 years ago
What is the solution?? <br>2sin^2 x +sinx +1=0
GenaCL600 [577]
The answer would be

#pi/2; (7pi)/6 and (11pi)/6#

Explanation ? 

Call sin x = t.
#2t^2 - t - 1 = 0.#
Since a + b + c = 0. use shortcut. 2 real roots: t = 1 and #t = c/a = -1/2#
sin x = t = 1 --> #x = pi/2#
sin x = t = -1/2 --> #x = (7pi)/6# and #x = (11pi)/6#

Within interval #(0, 2pi)#: 3 answers: #pi/2; (7pi)/6 , and (11pi)/6.#

-------------------------------------------------------------------------------------------

Hope you find this helpful !


7 0
3 years ago
HELPPP 20 PNTS
enot [183]

Answer:

25.1327cm

Step-by-step explanation:

C= 2πr

C=2π(4)

C=25.13274122

6 0
3 years ago
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