The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
2x=14
x=7
Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Given:
Train A:
Distance = 175 Miles
Time = 4 Hours
Train B:
y=43.5x
To Find:
which train travels at a faster rate in by what factor =?
Solution:
The speed of the train A = 
The speed of train A =
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line
The standard equation of the slope of the line is
y = mx+b
where m is the slope
and we are given with
y = 43.5x
So comparing with the standard equation
m = 43.5
Hence the speed of train B is 43.5 miles per hours
Train A travels faster


rate =1.01
Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
Answer:
a) 
b) 
Step-by-step explanation:
a) Let the required polynomial be p(x).
We have the relation,
+ p(x) = 18
i.e. p(x) = 18 
i.e. p(x) = 
b) Let the required polynomial be q(x).
We have the relation,
+ q(x) = 0
i.e. q(x) = 0 
i.e. q(x) = 